In the reaction
`underset(" (Adduct)")(NH_(3)+BF_(3)rarrNH_(3)*BF_(3))`
Choose the correct statement.

Options

A. Hybridisaton of 'N' in `NH_(3)` changes in adduct
B. Hybridisation of 'N' in adduct is `sp^(3)`
C. Here, `NH_(3)` is acting as a Lewis base while `BF_(3)` as a Lewis acid
D. Hybridisation of 'B' in `BF_(3)` changes in adduct

Answer

B, C, D

Explanation

`H-overset(H)overset(|)underset(H)underset(|)Nrarroverset(F)overset(|)underset(F)underset(|)B-F`