`PCl_(5)` is `10%` dissociated at `1 atm`. What is `%` dissociation at 4 atm . `PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)`

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

Write the Kp expression for PCl_(5(g))hArr PCl_(3(g)) + Cl_(2(g))

Write the Kp expression for PCl_(5(g))hArr PCl_(3(g)) + Cl_(2(g))

Write the Kp expression for PCl_(5(g))hArr PCl_(3(g)) + Cl_(2(g))

Write the Kp expression for PCl_(5(g))hArr PCl_(3(g)) + Cl_(2(g))

1 mole of PCl_(5) taken at 5 atm, dissociates into PCl_(3) and Cl_(2) to the extent of 50% PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) Thus K_(p) is :

1 mole of PCl_(5) taken at 5 atm, dissociates into PCl_(3) and Cl_(2) to the extent of 50% PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) Thus K_(p) is :