f(x)={[|x|cos((1)/(x)),,x!=0],[0,,x=0]

The value of c in Lagrange's theorem for the function f(x)={x cos((1)/(x)),x!=0 and 0,x=0 in the interval [-1,1] is

If the function f(x)={[(cos x)^((1)/(x)),x!=0k,x=0k,x=0]} is continuos at x=0 then the value of k]}

If f(x)={[(cos x)^((1)/(sin x)),,x!=0],[K,,x=0]} is differentiable at x=0 Then K=

f(x)={x^(2)cos((1)/(x)),x<0 and 0,x=0 and x^(2)sin((1)/(x)),x<0 then which of the following is (are) correct?

Show that the function f(x) defined as f(x)=cos((1)/(x)),x!=0;0,x=0 is continuous at x=0 but not differentiable at x=0..

Examine the continuity of a function f(x)={{:(|x|"cos"(1)/(x)", if "x!=0),(0", if "x=0):} at x=0 .

If f(x)={x^(a)cos(1/x),x!=0 and 0, x=0 is differentiable at x=0 then the range of a is

The function f(x)=x cos((1)/(x^(2))) for x!=0,f(0)=1 then at x=0,f(x) is

If f(x) = {{:((sin^(-1)x)^(2)cos((1)/(x))",",x ne 0),(0",",x = 0):} then f(x) is