`y^2+(x+1/y)(dy)/(dx)=0`

Solve the following differential equations (i) (1+y^(2))dx = (tan^(-1)y - x)dy (ii) (x+2y^(3))(dy)/(dx) = y (x-(1)/(y))(dy)/(dx) + y^(2) = 0 (iv) (dy)/(dx)(x^(2)y^(3)+xy) = 1

2 x y+y^2-2 x^2 (dy)/(dx)=0 , y=2 when x=1

The solution of differential equation (1+y^(2))+(x-e^(tan^(-1)y))(dy)/(dx)=0 , is

The solution of the differential equation (1 + y^(2)) + (x- e^(Tan^(-1)y)) (dy)/(dx) = 0 is

The solution of the differential equation (1+y^2)+(x-e^(tan^-1 y))(dy)/(dx)=0 , is

The solution of the differential equation : (1+y^2)+(x-e^(tan^(-1)y))(dy)/(dx)=0 is :