" (iii) "((2+3i)^(2))/((2-i))

Write the following in the form x+iy: (i) (3+2i)(2-i) (ii) 2i^(2)+6i^(3)+3i^(16)-6i^(19)+4i^(25) . (iii) ((3-2i)(2+3i))/((1+2i)(2-i)) .

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Prove that the following complex numbers are purely real: (i) ((2+3i)/(3+4i))((2-3i)/(3-4i)) (ii) ((3+2i)/(2-3i))((3-2i)/(2+3i))

Prove that: (i) [((3+2i)/(2-5i))+((3-2i)/(2+5i))] is rational (ii) [((2-3i)/(3-4i))((2+3i)/(3+4i))] is real.

The modulus of ((2+3i)^(2))/(2+i) is

The modulus of ((2+3i)^(2))/(2+i) is

Convert ((2+3i)^(2))/(2-i) in the form of a+ib and find its conjugate.

Convert ((2+3i)^(2))/(2-i) in the form of a+ib and find its conjugate.