Home
Class 12
PHYSICS
A closed organ pipe of length L is vibra...

A closed organ pipe of length L is vibrating in its first overtone there is a point Q inside the pipe at a distance `7L//9` form the open end the ratio of pressure amplitude at Q to the maximum pressure amplitude in the pipe is

A

`1:2`

B

`2:1`

C

`1:1`

D

`2:3`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaPm=2DeltaP_(0) coskx` (assuming closed end as origin)
At point `Q,x=L-(7L)/9=(2L)/9`
`DeltaPm=2DeltaP_(0)cos((2pi)/(lamda)xx(2L)/9)=DeltaP_(0)`
`:.` Required ratio `=1:2`
Promotional Banner

Similar Questions

Explore conceptually related problems

A closed organ pipe of length 1.2 m vibrates in its first overtone mode. The pressure variation is maximum at

A closed organ pipe of length 1.2 m vibrates in its first overtone mode . The pressue variation is maximum at

A closed organ pipe has length L . The air in it is vibrating in thirf overtone with maximum ampulitude a . The amplitude at distance (L)/(7) from closed of the pipe is

An open organ pipe has length l .The air in it vibrating in 3^( rd ) overtone with maximum amplitude A.The amplitude at a distance of (l)/(6) from any open end is.

A string of length L is fixed at both ends . It is vibrating in its 3rd overtone with maximum amplitude a. The amplitude at a distance L//3 from one end is

A closed organ pipe of length L is in resonance with a tuning fork. If a hole is made in the pipe at a distance L/4 from closed - end, it will be in resonance again, when:

An open organ pipe has length l .The air in it vibrating in 3^( rd ) overtone with maximum amplitude A . The amplitude at a distance of (l)/(16) from any open end is.

An open organ pipe has length l .The air in it vibrating in 3^( rd ) overtone with maximum amplitude A . The amplitude at a distance of (l)/(16) from any open end is

An open organ pipe of length L vibrates in its fundamental mode. The pressure variation is maximum