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Four metallic plates are sued to form tw...

Four metallic plates are sued to form two identical parallel plate capacitors as shown is the figure. Initially all plates were unchanged. Two batteries are connected to two capacitors `x` & `y` are equidistant from two plates. The magnitude of work done by electric field in moving electron from `x` to `y` is `WeV`. Find the value of `2W`

Text Solution

Verified by Experts

The correct Answer is:
7
Charge on each capacitor is
`q=(3C)/2`
Electric field between plates `=q/(Aepsilon_(0))`
`V_(x)+(Ed)/2-5+(Ed)/2=V_(y)`
`V_(y)-V_(x)=Ed-5`
`=q/(epsilon_(0)A)d-5=q/C-5=(3C//2)/C-5=3/2-5`
`=-3.5V`
`V_("el")=q(V_(y)-V_(x))=(-e)(-3.5)`
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