Home
Class 12
PHYSICS
A wedge is moving rightwards on which a ...


A wedge is moving rightwards on which a block of mass 10 kg is placed on it. Friction coefficient between the eedge and the block is 0.8. Select correct alternative (s) among the following options. [take `g=10(m)/(s^(2))`]

A

If wedge is moving with constant velocity then friction acting on block is `64N`

B

If wedge is moving with constant velocity then acceleration of block is zero

C

If wedge is moving with `veca=2(hati)m//s^(2)` then friction acting on block is `44N`

D

If wedge is moving with `veca=10(hati)m//s^(2)` then friction is `20N`, downward on the block along the inclined.

Text Solution

Verified by Experts

NA
Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass 1 kg is placed on a wedge shown in figure. Find out minimum coefficient of friction between wedge and block to stop the block on it.

A force of 100N is applied on a block of mass 3 kg as shown in the figure-2.164. The coefficient of friction between the surface and the block is 0.25.The frictional force acting on the block is: (Take g=10m/s^(2) )

A force F is applied on a block of mass 5 kg as shown in figure. Co-efficient of friction between the wall and clock is (sqrt(3))/(2). (g = 10m//s^(2)) Select correct option(s)

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

A force of 200N is applied as shown in the figure on block of 3 kg. The coefficient of friction between the block and the wall is 0.3. Find the friction acting on the block. (in N) {Take g = 10 m//s^(2)

A block of mass 50 kg slides over a horizontal distance of 1m. If the coefficient of friction between their surface is 0.2, then work done against friction is (take g = 9.8 m//s^(2) ) :

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

A vehicle is moving on a road with an acceleration a=20 m//s^(2) as shown in figure. The frictional coefficient between the block of mass (m) and the vehicle so that block is does not fall downward is (g=10m//s^(2))

A block of mass "5kg" is placed on a wedge having inclination of 37^(@) with the horizontal. Coefficient of friction between block and wedge is 0.8. Then select the correct statement.