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When the voltage applied to an X-ray tub...

When the voltage applied to an X-ray tube increased from `V_(1)=15.5kV` to `V_(2)=31kV` the wavelength interval between the `K_(alpha)` line and the cut-off wavelength of te continuous X-ray spectrum increases by a factor of `1.3`. If te atomic number of the element of the target is z. Then the value of `(z)/(13)` will be: (take `hc=1240eVnm` and `R=1xx(10^(7))/(m))`

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The correct Answer is:
2
`lamda_(th)=(hc)/(eV_(a))`
`1/(lamda_(Kalpha))=R(z-1)^(2)(1/(1^(2))-1/(2)^(2))`
`13/10 lamda_(k_(alpha))=(13/10-1/2)_(lamda_(th)`
`3/10((4xx10^(-7))/(3(z_(7))^(2)))=(8/10)(12.4xx10^(-7))/(15.5xx10^(3))implies5000/8`
`(z-1)^(2)`
`625=(z-1)^(2)impliesz=26`
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