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Figure elliptical path abed of a planet ...


Figure elliptical path abed of a planet around the sun S such that the area of Delta csa is `(1)/(4)` the area of the ellipse, (see figure) with db as the semimajor axis, and ca as the semiminor axis if `t_(1)` is the time taken for planet to go over path abc and `t_(2)` for path taken over cda then:

A

`t_(1)=3t_(2)`

B

`t_(1)=t_(2)`

C

`t_(1)=2t_(2)`

D

`t_(1)=4t_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Total area `=A`
Area of `sabc=(3A)/A`
Area of `sadc=A/4`
`(3A)/(4t_(1))=A/(4t_(2))impliest_(1)=3t_(2)`
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