Home
Class 12
PHYSICS
A hydrogen atom makes a transition from ...

A hydrogen atom makes a transition from `n=2` to `n=1` and emits a photon. This photon strikes a doubly ionized lithium atom `(Z=3)` in excited state and completely removes the orbiting electron. The least quantum number for the excited stated of the ion for the process is:

A

`4`

B

`5`

C

`2`

D

`3`

Text Solution

Verified by Experts

The correct Answer is:
A
Energy of proton `=13.6-3.4=10.2eV`
For removal of electron
`10.2eVgt13.6(z^(2))/(n^(2))`
`n^(2)gt13.69/10.2`
so minimum value o `n=4`
Promotional Banner

Similar Questions

Explore conceptually related problems

As an electron makes a transition from an excited state to the ground state of a hydrogen - like atom //ion

As an electron makes a transition from an excited state to the ground state of hydrogen-like atom // ion:

An electron makes transition form n=3 , n=1 state in a hydrogen atom. The maximum possible number of photons emitted will be

A photon of energy 12.09 eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is

The electron in a hydrogen atom makes a transition from an excited state to the fgeround state . Which of the following istrue ?

The electron in a hydrogen atom makes a transition from an excited state to the ground state. Which of the following statements is true?

An excited hydrogen atom returns to the ground state . The wavelength of emittted photon is lambda The principal quantium number fo the excited state will be :