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When current in a coil changes from 5 A ...

When current in a coil changes from 5 A to 2 A in 0.1 s, average voltage of 50 V is produced. The self - inductance of the coil is :

A

`1.67H`

B

`6H`

C

`3H`

D

`0.67H`

Text Solution

Verified by Experts

The correct Answer is:
A

`EMF=(Ldi)/(dt)`
`50=L(5-2)/(0.1 "sec")`
`implies L=(50xx0.1)/3=5/3=1.67H`
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