Home
Class 12
PHYSICS
A charged particle enters a uniform magn...

A charged particle enters a uniform magnetic field with velocity vector at angle of `45^@` with the magnetic field. The pitch of the helical path followed by the particle is p. the radius of the helix will be

A

`P/(sqrt(2)pi)`

B

`sqrt(2)P`

C

`P/(2pi)`

D

`(sqrt(2)P)/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(mvsintheta)/(qB)` & `P=(2pim vcostheta)/(qB)`
`:.r/P=(tantheta)/(2pi)=1/(2pi)`
`r=P/(2pi)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A charged enters a unifrom magnetic field with velocity vector at an angle of 45^(@) with the magnetic field . The pitch of the helical path followed by the particles is rho . The radius of the helix will be

When a charged particle enters a uniform magnetic field its kinetic energy

A charged particle enters into a magnetic field with velocity vector making an angle of 30^@ with respect of the direction of magnetic field. The path of the particle is

A charged particle enters a magnetic field at an angle of 90^(@) with the magnetic field. The path of the particle will be a/an

A charged particle enters a magnetic field H with its initial velocity making an angle of 45^(@) with H . The path of the particle will be

A charged particle enters a region of uniform magnetic field at an angle of 85@ to the magnetic line of force . The path of the particle is a circle .

A charged particle enters into a uniform magnetic field the parameter that remains constant is

A charged particle enters a uniform magnetic field perpendicular to it. The magnetic field

A proton enters a region of uniform magnetic field B of 0.5T with a velocity u at an angle 45^(@) with B .If P is the pitch of the helical path followed,the radius of the helix is :?