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A block of mass m(1) lies on top of fixe...

A block of mass `m_(1)` lies on top of fixed wedge as shown in figure 1 and another block of mass `m_(2)` lies on top of wedge which is free to move as shown in figure 2. At time `t=0`, both the blocks are released from rest from a vertical height `h` above the respective horizontal surface on which the wedge is palced as shown. There is no friction betwen block and wedge in both the figures. Let `T_(1)` and `T_(2)` be the time taken by block in figure 1 and block in figure 2 respectively to just reach the horizontal surface then:

A

`T_(1)gtT_(2)`

B

`T_(1)ltT_(2)`

C

Magnitude of normal reaction on block of mass `m_(2)` is equal to that on the block of mass `m_(1)`

D

After falling through same height (less than `h`) from top of wedge, the speed of block of mass `m_(2)` is less than that of block of mass `m_(1)`

Text Solution

Verified by Experts

The correct Answer is:
A

We draw axes of each along the incline and normal to incline. The component of acceleration for each block are as shown where is acceleration of wedge is figure 2.
It is obvious that vertical component of acceleration is larger for block in figure 2.
`:.T_(1)gtT_(2)`
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