Home
Class 12
PHYSICS
A bot of mass 30kg starts running from r...

A bot of mass `30kg` starts running from rest along a circular path of radius `6m` with constant tangential acceleration of magnitude `2m//s^(2)`. After `2sec` from start he feels that his shoes started slipping on ground. The friction coefficient between his shoes and ground is `mu`.
Find `2/(mu)`. (Take `g=10m//s^(2)`)

Text Solution

Verified by Experts

The correct Answer is:
6
After `2` sec speed of boy will be
`v=2xx=4m//s`
At this moment centripetal force on boy is
`F_(r)=(mv^(2))/R=(30xx16)/6=80Nt`.
Tagential force on boy is
`F_(t)=ma=30xx2=60Nt`.
Total friction action on boy is
`F=sqrt(F_(t)^(2)+f_(t)^(2))=100Nt`
At the time of slipping
`F=mug`
or `100=muxx30xx10`
`=mu=1/3`
Promotional Banner

Similar Questions

Explore conceptually related problems

A body of mass 30 kg starts running rest along a ciruclar path of radius 6m with constant tangential acceleration of magnitude 2 m//s^(2) . After 2 sec from start he feels that his shoes started slipping on ground. The friction coefficient between his shoes and ground is : ( Take g=10m//s^(2))

A particle of mass 2kg start motion form rest on a circular path of radius r=4m with constant tangential acceleration 4 ms^(-2) . Find the net work done on the particle in initial 1 second.

A body starts revolving from rest in a circular path of radius 2 m with tangential acceleration a =2tm//s^(2) . If its total acceleration at t=2 sec. is nsqrt(5) m//s^(2) , then the value of n is:

If a particle of mass m start from along curved circular path shown in figure with constant tangential acceleration a, then net force at B on the particle has the magnitude :

A body of mass 1 kg starts moving from rest t = 0 in a circular path of radius 8 m. Its kinetic energy varies with time as k = 2t^(2) J then magnitude of centripetal acceleration ( in m//s^(2) ) at t = 2s is.

A particle starts moving on circular path of radius (9)/(4)m with tangential acceleration 3ms^(-2) . Find angle between acceleration of the particle and radius vector at time t=1 sec.

A man starts running with constant speed along a circular path of radius sqrt2m He completes two rounds in 16 seconds. The magnitude of the average velocity in first 2 seconds is

A particle is moving on a circular path of radius 1 m with 2 m/s. If speed starts increasing at a rate of 2m//s^(2) , then acceleration of particle is

An atheletic completes a circular loop moving with maximum constant speed in 10 sec. what is the radius r (in m) of the loop if friction coefficient between his shoes and ground is 0.8. fill r/10 in OMR sheet. Take pi^(2)=10 .