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A particle moves along a constant curvat...

A particle moves along a constant curvature path between `A` and `B` (length of curve wire `AB` is `100m`) with a constant speed of `72km//hr`. The acceleration of particle at mid point `'C'` of curve `AB` is

A

Zero

B

`3.14m//s^(2)`

C

`50.84m//s^(2)`

D

`50.84km//hr^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`a_(C)=(|bar(v)|^(2))/R=((20)^(2))/(400/(pi))=pim//s^(2)`
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