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When identical point charges are placed ...

When identical point charges are placed at the vertices of a cube of edge length `'a'` each of them experiences a net force of magnitude `F`.
Now these charges are placed on the vertices of another cube of edge length `'b'`. What will be magnitude of the net force on any of the charges? These cubes are simply geometrical constructs and not made by any matter.

A

`(a^(2)F)/(b^(2))`

B

`(b^(2)F)/(a^(2))`

C

`(aF)/b`

D

Insufficient information

Text Solution

Verified by Experts

The correct Answer is:
A

`F_(1)alpha1/(a^(2))`
`F_(2)prop1/(b^(2))`
`(F_(1))/(F_(2))=(b^(2))/(a^(2))`
`F_(2)=(a^(2))/(b^(2)) F_(1)=(a^(2))/(b^(2))F`
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