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We have a thin spherical of radius R. Ha...

We have a thin spherical of radius `R`. Half of the sphere carrying surface change density `sigma_(1)` and rest half carrying `sigma_(2)`. Magnitude of force of electromagnetic interaction between hemispherical parts carrying surface charge density `sigma_(1)` and rest of the hemispherical portion is `f_(0)=alphaxx10^(4)` Newton. Here `alpha` is an integer. Value of `alpha` will be.
Given `sigma_(1)sqrt(epsilon_(0))xx10^(2)cm//m^(2),sigma_(2)=4sigma_(1),R=sqrt(3/(pi)m)`

A

`3`

B

`4`

C

`5`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
D
`f=(piR^(2))/(2epsilon_(0)) sigma_(1) sigma_(2)`
`=pi 3/(pi) 1/(2epsilon_(0)) 4epsilon_(0)xx10^(4)=6xx10^(4)N`
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