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Rod AB of length 1m is released from the...

Rod `AB` of length `1m` is released from the shown position. End `A` undergoes perfect inelastic collision with ground `C` is mid-point of rod. Angular velocity of rod just after collision is `(3x)/2rad//sec`. Find `x`. (Assuming no slipping on ground)

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The correct Answer is:
5
Conserving angular momentum about point of impact.
`msqrt(2gh).L/2sintheta=(mL^(2))/3omega`
`impliesomega=3/2sin30^(@).(sqrt(2xxgH))/L=15/2rad//sec`
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