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Given alpha+beta+gamma=pi then sin^2alph...

Given `alpha+beta+gamma=pi` then `sin^2alpha+sin^2beta-sin^2gamma` is equal to……

A

`2 sin alpha.sin beta.cos gamma`

B

`4 sin alpha sin beta. Sin gamma`

C

`2 cos alpha.sin gamma.cos beta`

D

`cos^2 alpha+cos^2 beta+cos^2 gamma`

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The correct Answer is:
A
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