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In hydrogen atom, the electron makes 6.6...

In hydrogen atom, the electron makes `6.6 xx 10^(15)` revolutions per second around the nucleus in an orbit of radius `0.5 xx 10^(-10)m`. It is equivalent to a current nearly

A

`1A`

B

`1mA`

C

`1 muA`

D

`1.6 xx 10^(-19)A`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equivalent current due to the electron revolving around the nucleus in a hydrogen atom, we can follow these steps: ### Step 1: Understand the relationship between current, charge, and time Current (I) is defined as the charge (Q) passing through a point in a circuit per unit time (T). Mathematically, this is expressed as: \[ I = \frac{Q}{T} \] ### Step 2: Determine the charge of the electron The charge of an electron (Q) is approximately: \[ Q = 1.6 \times 10^{-19} \text{ C} \] ### Step 3: Calculate the time period (T) of one revolution The time period (T) can be calculated using the frequency (f), which is given as \( 6.6 \times 10^{15} \) revolutions per second. The time period is the reciprocal of frequency: \[ T = \frac{1}{f} \] Substituting the value of frequency: \[ T = \frac{1}{6.6 \times 10^{15}} \text{ seconds} \] ### Step 4: Calculate the current (I) Now, substituting the values of Q and T into the current formula: \[ I = \frac{Q}{T} = Q \times f \] Substituting the values: \[ I = (1.6 \times 10^{-19} \text{ C}) \times (6.6 \times 10^{15} \text{ Hz}) \] ### Step 5: Perform the calculation Calculating the above expression: \[ I = 1.6 \times 6.6 \times 10^{-19 + 15} \] \[ I = 10.56 \times 10^{-4} \text{ A} \] \[ I \approx 1.056 \times 10^{-3} \text{ A} \] \[ I \approx 1.056 \text{ mA} \] ### Conclusion The equivalent current due to the electron revolving around the nucleus in a hydrogen atom is approximately: \[ I \approx 1.056 \text{ mA} \]
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ERRORLESS -CURRENT ELECTRICITY-Self Evaluation Test -19
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