The resistance of a coil is 4.2Omega at ...

The resistance of a coil is `4.2Omega` at `100^(@)C` and the temperature coefficient of resistance of its material is `(0.004)/(.^(@)C)`. Its resistance at `0^(@)C` is

`6.5 Omega`

`5 Omega`

`3 Omega`

`4 Omega`

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The resistance of a coi is 4.2Omega at 100^(@)C and the temperature coefficient of resistance of its material is (0.004)/(.^(@)C) . Its resistance at 0^(@)C is

If the resistance of a conductor is 5 Omega at 50^(@)C and 7Omega at 100^(@)C then the mean temperature coefficient of resistance of the material is

A tungsten coil has a resistance 16 Omega at 20^@C . If the temperature coefficient of resistance of tungsten is 0.004^@C^(-1) , calculate the resistance of the coil at 80^@C .

The resistance of a metallic conductor is 50Omega at a temperature of 100^(@)C .If its temperature coefficient of resistance is 0.005^(@)C^(-1) ,then its resistance will become 125Omega at a temperature of

A conductor has resistance of 5 Omega at 60^@C and 6 Omega at 100 ^@C . Find (i) the mean temperatures coefficient of resistance of the material of conductor and (ii) resistance at 0^@C .

The resistance of the bulb filament is 100Omega at a temperature of 100^(@)C . If its temperature co-efficient of resistance be 0.005 per 5 ""^(@)C , its resistance will becomes 200 Omega at a temperature

The resistance of a bulb filmanet is 100Omega at a temperature of 100^@C . If its temperature coefficient of resistance be 0.005 per ^@C , its resistance will become 200 Omega at a temperature of

A metal wire of diameter 2 mm and length 100 m has a resistance of 0.5475 Omega " at " 20^(@)C and 0.805 Omega " at " 150^(@)C . Find (i) the temperature of coefficient of resistance (ii) resistance at 0^(@)C (iii) resistivities at 0^(@) and 20^(@)C .

A wire has a resistance of 3.1 Omega at 30°C and a resistance 4.5 Omega at 100°C. The temperature coefficient of resistance of the wire

ERRORLESS -CURRENT ELECTRICITY-Self Evaluation Test -19

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