Three resistances of magnitude 2, 3 and 5 ohm are connected in parallel to a battery of 10 volts and of negligible resistance. The potential difference across `3 Omega` resistance will be

Options

A. 2 volts
B. 3 volts
C. 5 volts
D. 10 volts

Answer

To solve the problem of finding the potential difference across the 3 ohm resistor when three resistances (2 ohm, 3 ohm, and 5 ohm) are connected in parallel to a 10-volt battery, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Configuration**:
- We have three resistors: R1 = 2 ohms, R2 = 3 ohms, and R3 = 5 ohms connected in parallel to a battery of 10 volts.

2. **Identify the Voltage Across Each Resistor**:
- In a parallel circuit, the voltage across each resistor is the same and equal to the voltage of the battery. Therefore, the voltage across each resistor (including the 3 ohm resistor) is 10 volts.

3. **Conclusion**:
- Since all resistors in parallel experience the same potential difference, the potential difference across the 3 ohm resistor is 10 volts.

### Final Answer:
The potential difference across the 3 ohm resistor is **10 volts**.

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