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A wire of resistance R is cut into ‘ n ’...

A wire of resistance R is cut into ‘ n ’ equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be

A

nR

B

`(R)/(n)`

C

`(n)/(R)`

D

`(R)/(n^(2))`

Text Solution

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The correct Answer is:
To find the equivalent resistance of a wire of resistance \( R \) that is cut into \( n \) equal parts and connected in parallel, we can follow these steps: ### Step-by-Step Solution: 1. **Determine the Resistance of Each Part:** - When the wire of resistance \( R \) is cut into \( n \) equal parts, the resistance of each part \( R_1 \) can be calculated using the formula: \[ R_1 = \frac{R}{n} \] - This is because resistance is directly proportional to the length of the wire, and cutting it into \( n \) equal parts reduces the length of each part. 2. **Set Up the Parallel Resistance Formula:** - When these \( n \) parts are connected in parallel, the equivalent resistance \( R_{eq} \) can be calculated using the formula for resistances in parallel: \[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n} \] - Since all resistances \( R_1, R_2, \ldots, R_n \) are equal, we can simplify this to: \[ \frac{1}{R_{eq}} = n \cdot \frac{1}{R_1} \] 3. **Substitute the Value of \( R_1 \):** - Substitute \( R_1 = \frac{R}{n} \) into the equation: \[ \frac{1}{R_{eq}} = n \cdot \frac{1}{\frac{R}{n}} = n \cdot \frac{n}{R} = \frac{n^2}{R} \] 4. **Calculate the Equivalent Resistance:** - Now, take the reciprocal to find \( R_{eq} \): \[ R_{eq} = \frac{R}{n^2} \] ### Final Answer: The equivalent resistance of the combination is: \[ R_{eq} = \frac{R}{n^2} \]
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