Home
Class 12
PHYSICS
In a circuit 5 percent of total current ...

In a circuit 5 percent of total current passes through a galvanometer. If resistance of the galvanometer is G then value of the shunt is

A

`19G`

B

`20G`

C

`(G)/(20)`

D

`(G)/(19)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of the shunt resistance \( S \) when 5% of the total current passes through a galvanometer with resistance \( G \), we can follow these steps: ### Step 1: Define the total current Let the total current in the circuit be \( I \). ### Step 2: Calculate the current through the galvanometer Since 5% of the total current passes through the galvanometer, the current through the galvanometer \( I_G \) can be expressed as: \[ I_G = 0.05 I \] ### Step 3: Calculate the current through the shunt The remaining current that passes through the shunt \( I_S \) is: \[ I_S = I - I_G = I - 0.05 I = 0.95 I \] ### Step 4: Apply the current divider rule In a parallel circuit, the current through each branch can be calculated using the current divider rule. The current through the galvanometer is given by: \[ I_G = \frac{S}{G + S} \cdot I \] Substituting \( I_G = 0.05 I \) into the equation gives: \[ 0.05 I = \frac{S}{G + S} \cdot I \] ### Step 5: Simplify the equation We can cancel \( I \) from both sides (assuming \( I \neq 0 \)): \[ 0.05 = \frac{S}{G + S} \] ### Step 6: Cross-multiply to solve for \( S \) Cross-multiplying gives: \[ 0.05 (G + S) = S \] Expanding this results in: \[ 0.05 G + 0.05 S = S \] ### Step 7: Rearrange the equation Rearranging the equation to isolate \( S \): \[ 0.05 G = S - 0.05 S \] \[ 0.05 G = 0.95 S \] ### Step 8: Solve for \( S \) Now, we can solve for \( S \): \[ S = \frac{0.05 G}{0.95} = \frac{G}{19} \] ### Conclusion Thus, the value of the shunt resistance \( S \) is: \[ S = \frac{G}{19} \]
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    ERRORLESS |Exercise Kirchhoff s Law, cells|8 Videos
  • CURRENT ELECTRICITY

    ERRORLESS |Exercise Different Measuring Instruments|1 Videos
  • COMMUNICATION SYSTEM

    ERRORLESS |Exercise S E T|14 Videos
  • ELECTRO MAGNETIC INDUCTION

    ERRORLESS |Exercise SET|20 Videos

Similar Questions

Explore conceptually related problems

Assertion : In a shunted galvanometer, only 10% current passes through the galvanometer. The resistance of the galvanometer is G. Then resistance of the shunt is G/9. Reason : If S is the shunt, then voltage across S and G is same.

In an ammeter 10% of main current is passing through the galvanometer. If the resistance of the galvanometer is G, then the shunt resistance, in ohms is

In a ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G , the resistance of ammeter will be

In an ammeter 0*2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be

In an ammeter 5% of the main current is passing through the galvanometer. If the resistance of galvanometer is G, then the resistance of shunt S will be

If only 1% of the total current is to be passed through a galvanometer of resistance G, then resistance of the shunt will be

If 2% current passes through galvanometer. Shunt resistance is 5 ohms then resistance of galvanometer is what?

ERRORLESS -CURRENT ELECTRICITY-Self Evaluation Test -19
  1. In a circuit 5 percent of total current passes through a galvanometer....

    Text Solution

    |

  2. Figure 6.51 shows a simple a potentiometer circuit for measuring a sma...

    Text Solution

    |

  3. A car has a fresh storage battery of emf 12 V and internal resistance ...

    Text Solution

    |

  4. If the balance point is obtained at the 35th cm in a metre bridge the ...

    Text Solution

    |

  5. The equivalent resistance across the terminals of source of e.m.f. 24 ...

    Text Solution

    |

  6. In the circuit shown in figure, switch S is initially closed and S i...

    Text Solution

    |

  7. The figure here shows a portion of a circuit. What are the magnitude a...

    Text Solution

    |

  8. A carbon resistor has colour strips as violet, yellow brown and golden...

    Text Solution

    |

  9. A voltmeter of resistance 1000 Omega is connected across a resistance ...

    Text Solution

    |

  10. A beam contains 2 xx 10^(8) doubly charged positive ions per cubic cen...

    Text Solution

    |

  11. In the circuit shown, the reading of ammeter when switch S is open ...

    Text Solution

    |

  12. In the circuit as shown in figure the

    Text Solution

    |

  13. In figure shows a rectangular block with dimensions x , 2 x and 4 x ....

    Text Solution

    |

  14. A battery is connected to a uniform resistance wire AB and B is eart...

    Text Solution

    |

  15. A cylindrical metal wire of length l and cross sections area S , has...

    Text Solution

    |

  16. A potential divider is used to give outputs of 4 V and 8 V from a 12 V...

    Text Solution

    |

  17. Find equivalent resistance between A and B

    Text Solution

    |

  18. Following figures show four situations in which positive and negative ...

    Text Solution

    |

  19. A and B are two square plates of same metal and same thickness but len...

    Text Solution

    |

  20. A moving coil galvanometer is converted into an ammeter reads upto 0.0...

    Text Solution

    |

  21. Two conductors are made of the same material and have the same length....

    Text Solution

    |