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A galvanometer coil of resistance 50 Ome...

A galvanometer coil of resistance `50 Omega`, show full deflection of `100 muA` . The shunt resistance to be added to the galvanometer, to work as an ammeter of range 10 mA is

A

`5 Omega` in parallel

B

`0.5 Omega` in series

C

`5 Omega` in series

D

`0.5 Omega` in parallel

Text Solution

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The correct Answer is:
To find the shunt resistance \( R \) that needs to be added to the galvanometer in order to convert it into an ammeter with a range of 10 mA, we can follow these steps: ### Step 1: Identify Given Values - Resistance of the galvanometer, \( R_g = 50 \, \Omega \) - Full-scale deflection current of the galvanometer, \( I_g = 100 \, \mu A = 100 \times 10^{-6} \, A \) - Desired maximum current for the ammeter, \( I = 10 \, mA = 10 \times 10^{-3} \, A \) ### Step 2: Determine the Current through the Shunt The current through the shunt resistance \( R \) can be calculated as: \[ I_R = I - I_g \] Substituting the values: \[ I_R = 10 \times 10^{-3} \, A - 100 \times 10^{-6} \, A = 10 \times 10^{-3} \, A - 0.1 \times 10^{-3} \, A = 9.9 \times 10^{-3} \, A \] ### Step 3: Apply the Voltage Equality Condition Since the galvanometer and the shunt are in parallel, the voltage across both must be equal: \[ V_g = V_R \] The voltage across the galvanometer is given by: \[ V_g = I_g \cdot R_g = (100 \times 10^{-6} \, A) \cdot (50 \, \Omega) = 5 \times 10^{-3} \, V \] The voltage across the shunt resistance is: \[ V_R = I_R \cdot R \] Setting these equal gives: \[ I_g \cdot R_g = I_R \cdot R \] ### Step 4: Substitute Known Values Substituting the known values into the equation: \[ (100 \times 10^{-6} \, A) \cdot (50 \, \Omega) = (9.9 \times 10^{-3} \, A) \cdot R \] This simplifies to: \[ 5 \times 10^{-3} \, V = (9.9 \times 10^{-3} \, A) \cdot R \] ### Step 5: Solve for Shunt Resistance \( R \) Rearranging the equation to solve for \( R \): \[ R = \frac{5 \times 10^{-3} \, V}{9.9 \times 10^{-3} \, A} \] Calculating \( R \): \[ R \approx \frac{5}{9.9} \, \Omega \approx 0.505 \, \Omega \] ### Final Answer The shunt resistance \( R \) that needs to be added to the galvanometer is approximately: \[ R \approx 0.51 \, \Omega \]
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