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A deutron of kinetic energy 50 keV is de...

A deutron of kinetic energy `50` keV is describing a circular orbit of radius `0.5` meter in a plane perpendicular to magnetic field `vecB`. The kinetic energy of the proton that describes a circular orbit of radius `0.5` meter in the same plane with the same `vecB` is

A

`258 keV`

B

`50keV`

C

`200 keV`

D

`100 keV`

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The correct Answer is:
D
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ERRORLESS -MAGNETIC EFFECT OF CURRENT-Exercise
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