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A proton enters a magnetic fiedl of flux...

A proton enters a magnetic fiedl of flux density `1.5"weber"//m^(2)` with a velocity of `2xx10^(-7)m//sec` at an angle of `30^(@)` with the field. The force on the proton will be

A

`2.4xx10^(-12)N`

B

`0.24xx10^(-12)N`

C

`24xx10^(-12)N`

D

`0.02xx10^(-12)N`

Text Solution

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The correct Answer is:
A
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ERRORLESS -MAGNETIC EFFECT OF CURRENT-Exercise
  1. Lorentz force can be calculated by using the formula.

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  2. A magnetic field

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