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A proton moving withh a velocity 2.5xx10...

A proton moving withh a velocity `2.5xx10^(7)m//s` enters a magnetic field of intensity `2.5T` making an angle `30^(@)` with the magnetic field. The force on the proton is

A

`3xx10^(-12)N`

B

`5xx10^(-12)N`

C

`6xx10^(-12)N`

D

`9xx10^(-12)N`

Text Solution

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The correct Answer is:
B
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ERRORLESS -MAGNETIC EFFECT OF CURRENT-Exercise
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