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AB and CD are long straight conductor, d...

`AB` and `CD` are long straight conductor, distance `d` apart, carrying a current `I`. The magnetic field at the midpoint of `BC` is

A

`(-mu_(0)I)/(2pid)hatk`

B

`(-mu_(0)I)/(pid)hatk`

C

`(-mu_(0)I)/(4pid)hatk`

D

`(-mu_(0)I)/(8pid)hatk`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • AB and CD are long straight conductor, distance d apart, carrying a current l. The magnetic field at the midpoint of BC is

    A
    `(-mu_(0)I)/(2pid)hatk`
    B
    `(-mu_(0)I)/(pid)hat k`
    C
    `(-mu_(0)I)/(4pid)hat k`
    D
    `(-mu_(0)I)/(8pid)hat k`

  • AB and CD are long staright conductors, distance d apart, carrying a current I . The magnetic field on BC due to the currents in AB and CD

    A
    is zero at all points
    B
    is zero at this midpoint
    C
    has different magnitudes at different points
    D
    is maximum at its midpoints

  • Shown in the figure is a conductor carrying a current i. the magnetic field at the origin is :

    A
    `(mu_(0) i)/(4r) ((hat(i))/(pi) + (hat(j))/(2))`
    B
    `- (mu_(0) i)/(4r) ((hat(i))/(pi) + (hat(k))/(2))`
    C
    `(mu_(0) i)/(4 r) ((hat(i))/(2) + (hat(i))/(pi))`
    D
    `(mu_(0) i)/(4r) ((2hat(i))/(pi) + hat(j))`

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