Home
Class 12
CHEMISTRY
At 80^(@)C the vapour pressure of pure l...

At `80^(@)C` the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of 'A' and 'B' boils at `80^(@)C` and 1 atm pressure, the amount of 'A' in the mixture is (1 atm `= 760 mm Hg)`

Promotional Banner

Similar Questions

Explore conceptually related problems

At 80^(@)C , the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture of solution of 'A' and 'B' boils at 80^(@)C and 1 atm pressure, the amount of 'A' in the mixture is ( 1 atm =760 mm Hg.)

At 80^(@)"C" , the vapour pressure of pure liquid 'A' is 250 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of 'A' and 'B' boils at 80^(@)"C" and 1 atm pressure, the amount of 'A' in the mixture is : "(1 atm=760 mm of Hg)"

At 80^(@)C the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 1000 mm Hg. If a mixture solution of A and B boils at 80^(@)C and 1 atm pressure, then amount of A in the mixture is

At 80^(@)C , the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of A and B boil at 80^(@)C and 1 atm pressure, than the amount of A in the mixture is (! Atm = 760 mm Hg)

At 80^@C , the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 1000 mm Hg . If a mixture of solution A and B boils at 80@C and 1 atm pressure, the amount of A in the mixture is (1 atm =760 mm Hg) a. 50 mol % , b. 52 mol % ,c. 34 mol% ,d. 48 mol %

At 80^@C , the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 1000 mm Hg . If a mixture of solution A and B boils at 80@C and 1 atm pressure, the amount of A in the mixture is (1 atm =760 mm Hg) a. 50 mol % , b. 52 mol % ,c. 34 mol% ,d. 48 mol %