`lim_(theta->0)[(12sintheta)/theta]+[(13tantheta)/theta]=k` where [*] denotes greatest integer, then `[k/5]` is equal to :

lim_ (theta-> 0) ([(nsintheta) / theta] + [(ntantheta) / theta]) where [] represents the greatest integer function

The limit underset( theta rarr0 ) ("lim") ([ (nsin theta)/( theta) ]+ [ ( n tan theta )/( theta)] ) ,n in N is ( where [ **] denotes greatest integer function )

lim_(x->0) ([(-5sinx)/x]+[(6sinx)/x] .(where [-] denotes greatest integer function) is equal to

Q.lim_(theta rarr(pi)/(2))[(theta-(pi)/(2))/(cos theta)], Iwhere denotes the greatest integer functionl is

The number of solutions of the equations y=1/3[sin theta+[sin theta +[sin theta]]] and [y+[y]]=2 cos theta [ where , [.] denote the greatest integer function ] is/are

The number of solutions of the equations y=1/3[sin theta+[sin theta +[sin theta]]] and [y+[y]]=2 cos theta [ where , [.] denote the greatest integer function ] is/are

The number of solutions of the equations y=1/3[sin theta+[sin theta +[sin theta]]] and [y+[y]]=2 cos theta [ where , [.] denote the greatest integer function ] is/are

The number of solutions of the equations y=1/3[sin theta+[sin theta +[sin theta]]] and [y+[y]]=2 cos theta [ where , [.] denote the greatest integer function ] is/are

Prove that lim_(theta to 0)(sintheta)/(theta)=1"("theta measured in radians)

if f(n,theta)=prod_(r=1)^(n) (1-tan^(2)(theta)/(2^(r))) then the value of lim_(thetato0) [lim_(ntoinfty) f(n,theta)] , (where [x] represent the greatest integer function) is