If the equation `a x^2+2b x-3c=0` has no real roots and `((3c)/4)<1+b ,` then `c<0` (b) `c >0` `c=0` (d) None of these

If the equation ax^(2)+2bx-3c=0 has no real roots and ((3c)/(4)) 0c=0 (d) None of these

If the equation ax^(2) + 2 bx - 3c = 0 has no real roots and (3c)/(4) lt a + b , then

ax^(2)+2bx-3c=0 has no real root and a+b>3(c)/(4) then

If the equation ax^(2) + 2bx - 3c = 0 has non-real roots and ((3c)/(4)) lt (a + b) , then c is always :

If c>0 and the equation 3ax^(2)+4bx+c=0 has no real root,then

If the equation ax^(2)+25x-3c=0 has non real roots and (3c)/4lt(a+b), then c is always (A) Negative (B) 0(C) Non-negative (D) zero

if the equation ax^(2)+2bx-3c=0 has non real roots and 3(c)/(4)

Given that a x^2+b x+c=0 has no real roots and a+b+c 0 d. c=0

Given that a x^2+b x+c=0 has no real roots and a+b+c 0 d. c=0