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1 g of graphite is burnt in a bomb calor...

1 g of graphite is burnt in a bomb calorimeter in excess of `O_(2)` at 298 K and 1 atm. Pressure according to the equations.
`C_("graphite")+O_(2(g)) to CO_(2(g))`
During the reaction the temperature rises from 298 K to 200K. Heat capacity of the bomb calorimeter is `20.7KJK^(-1)`. What is the enthalpy change for the above reaction at 298 K 1 atm?

Text Solution

Verified by Experts

Heat is absorbed by calorimeter `=C_(v).DeltaT=(20.7KJK^(-1))xx1=20.7 KJ`
Heat evolved during combustion of 1 gm of graphite `=-20.7KJ`
`Delta_(c)H^(theta)=(-20.7xx12)/(1)=248.3KJ`
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