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Given N(2)(g)+3H(2)(g)to2NH(3)(g),Delta(...

Given `N_(2)(g)+3H_(2)(g)to2NH_(3)(g),Delta_(r)H^(theta)=-92.4 kJ mol^(-1)` What is the standard enthalpy of formation of `NH_(3)` gas ?

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The heat of reaction `Delta_(r)H^(theta)` is -92.4 kJ `mol^(-1)`
This is the of formation of 2 moles of ammonia.
The enthalpy of formation of 1 mol of `NH_(3)=(-92.4)/(2)=-46.2 kJ`
`therefore` Standard enthalpy of formation of ammonia = -46. 2 kJ
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