Calculate the enthalpy change for the process
`"CC"l_(4)(g)toC(g)+4CI(g)`
and calculate bond enthalpy of `C-Cl in C Cl_(4)(g).`
`Delta_("vap")H^(theta)("C C"l_(4))=30.5 kJ mol^(-1)`.
`Delta_(f)H^(theta)(CCl_(4))=-135.5 kJ mol^(-1)`.
`Delta_(0)H^(theta)(C)=715.0 kJ mol^(-1)`, where `Delta_(a)H^(theta)` is enthalpy of atomisation.
`Delta_(a)H^(theta)(Cl_(2))=242 kJ mol^(-1)`.

Explanation

`C(s)+2Cl_(2)(g)to"CC"l_(4)(l)`
`therefore DeltaH=715 +(2xx242)-4e_(C-Cl)-DeltaH_("vap")`
`-135.5=119-4e_(C-Cl)-30.5`
`4e_(C-Cl)=1304`
`"CC"l_(4)toC+4Cl=DeltaH=1304 kJ`
Bond energy of `C-Cl=(1304)/(4)=326 kJ`