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For the reaction at 298 K, 2A+BtoC D...

For the reaction at 298 K,
`2A+BtoC`
`DeltaH=400 kJ mol^(-1) and DeltaS=0.2 kJ K^(-1)mol^(-1).`
At what temperature will the reaction becomes spontaneous considering `DeltaH and DeltaS` to be constant over the temperature range?

Text Solution

Verified by Experts

At equilibrium `DeltaG=0`
`T_("equl")=(DeltaH)/(DeltaS)=(400)/(0.2)=2000K`
The reaction is spontaneous over `2000^(@)k.`
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