State law of chemical equilibrium? What is `K_(c)` for the following equilibrium when the equilibrium concentration of each substance is `[SO_(2)]=0.60M,[O_(2)]=0.82M` and `[SO_(3)]=1.90M`
`2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g)`

Explanation

Law of chemical equilibrium: At a given temperature the product of concentrations of the reaction products raised to the respective stoichiometric coefficients in the balanced chemical equation divided by the product of concentrations of the reactants raised to their individual stoichiometric coefficient has a constant value.
`2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g)`
`K_(c)=([SO_(3)]^(2))/([SO_(2)]^(2)[O_(2)])=((1.9)^(2))/((0.6)^(2)(0.82))`
`=12.229 "mol"L^(-1)`