Describe the effect of:
a. addition of `H_(2)`
b. addition of `CH_(3)OH`
c. removal of CO
d. removal of `CH_(3)OH` on the equilibrium of the reaction.
`2H_(2)(g)+CO(g)hArrCH_(3)OH(g)`

Explanation

a. According to Le Chatelier's principle increase in the concentration of reactant increase the forward reaction.
so the addition of `H_(2)` results in the formation of more amount of `CH_(3)OH`.
b. According to Le Chatelier's principle increase in the concentration of the product shift the equilibrium in the backward direction.
So the addition of `CH_(3)OOH` (product) results in the decrease in concentration and `CH_(3)OH` and increase in the concentration of `H_(2)` and `CO`.
c. According to Le Chatelier's principle the decrease in the concentration of reactant equilibrium shift in the backward direction. So removal fo CO (reactant ) the equilibrium shift in the backward direction. So formation of `CH_(3)OH` decreases.
d. According to Le Chatelier's principle the decrease in concentration of product shifts the equilibrium in the forward direction. So the removal of `CH_(3)OH` (product) shift the equilibrium in the forward direction. Thus more amount of `CH_(3)OH` is formed.