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At 27^(@)C, K(p) value for the reversibl...

At `27^(@)C, K_(p)` value for the reversible reaction `PCl_(5)(g)harrPCl_(3)(g)+Cl_(2)(g)` is 0.65, calculate `K_(c)`.

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`K_(p)=K_(c)[RT]^(Deltan)`
`PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)`
For this reaction `Deltan=2-1=1`
`K_(c)=(K_(p))/([RT]^(Deltan))=0.65/(0.821xx300)=0.0264`
`:.` Equilibrium constant `K_(c)=0.0264`
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