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For the following reaction PCl(5)(g)hA...

For the following reaction
`PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)0.4` mole of `Cl_(2)` are taken in a 1 litre flask. If `K_(c)=0.2` predict the direction in which reaction proceeds.

Text Solution

Verified by Experts

`underset(0.4)(PCl_(5))(g)hArr underset(0.2)(PCl_(3))(g)+underset(0.6 "initial concentrations")(Cl_(2))(g)`
`Q=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(0.2xx0.6)/0.4=0.3`
`K_(c)=0.2`
Q is greater than `K_(c)` . So reaction takes place in bacward direction.
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