A vessel at `100K` contains `CO_(2)` with a pressure of 0.5 atm. Some of the `CO_(2)` is converted into CO on addition of graphite. Calculate the value of K if total pressure at equilibrium is 0.8 atm.

Explanation

`underset(0.5-x)underset(0.5)(CO_(2))+underset(0)underset(0)(C)hArrunderset(2x "equilibrium conc.")underset(0"initial conc.")(2CO)`
total pressure at equilibrium `=0.8`
equilibrium mixture contains CO and `CO_(2)`
`:.(0.5+x) atm=0.8 atm`
`x=0.3` atm
`K_(p)=((0.6)^(@))/0.2=1.8` atm