The `K_(p)` values for the reaction
`H_(2)(g)+I_(2)(g)hArr2HI(g)` at `460^(@)C` is 49. If the initial pressure of `H_(2)` and `I_(2)` are 0.5 atm respectively, determine the partial pressure of each gases at equilibrium.

Explanation

`underset(0.5-x)underset(0.5)(H_(2))+underset(0.5-x)underset(0.5)(I_(2))hArr underset(2x "equilibrium conc.")underset(0 "initial conc.") (2HI)`
Given that `K_(c)` for the above reaction `=49`.
`49=([HI]^(2))/([H_(2)][I_(2)])=((2x)/(0.5-x))^(2)`
`sqrt(49)=(2x)/(0.5-x)=7`
`[H_(2)]=[I_(2)]=0.5-x=0.11` atm
`[HI]=2x=0.778` atm.