What is `[H^(+)]` for a solution in which
a. `pH=3` b. `pH=4.75` c. `pH=4.4`?

Explanation

a. `pH=3`
`[H^(+)]=10^(-3)M`
b. `pH=4.75`
`-log[H^(+)]=4.75`
`[H^(+)]=10^(-4.75)`
`=10^(-5)xx "antilog" 0.25`
`=1.778xx10^(-5)M`
c. `pH=4.4`
`-log[H^(+)]=4.4`
`[H^(+)]=10^(-4.4)`
`=10^(-5)xx10^(0.6)`
`=10^(-5)xx` antilog 0.6
`=3.981xx10^(-6)M`