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A solutioin of 0.005 MH(2)SO(4) is dilut...

A solutioin of 0.005 `MH_(2)SO_(4)` is diluted 100 times. Calculate the pH of diluted solution.

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`M_(1)V_(1)=M_(2)V_(2)`
`M_(1)=0.005 M_(2)=?`
`V_(1)=1V_(2)=100`
`M_(2)=(0.005xx1)/100=5xx10^(-5)`
`H_(2)SO_(4)to2H^(+)+SO_(4)^(2-)`
`5xx10^(-5) 10xx10^(-5)`
`pH=-log[H^(+)]=-log[1xx10^(-4)]=4`
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