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Caculate the pH of 10^(-8) mNaOH...

Caculate the pH of `10^(-8) mNaOH`

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`[OH^(-)]=10^(-8)+10^(-7)`
`=0.1xx10^(-8)+1xx10^(-7)=1.1xx10^(-7)`
`pOH=-log[1.1xx10^(-7)]=6.96`
`pH=14-6.96\7.04`
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