Calculate the p of solution obtained by mixign 10 ml fo 0.1 M HCl and 40 ml off `0.2 M H_(2)SO_(4)`.

Explanation

`H_(2)SO_(4)to2H_(+)+SO_(4)^(2-)`
`0.2M, 0.4M`
`HCl, to H^(+)+Cl^(-)`
`0.1, 0.1`
`[H^(+)]=(V_(1)M_(1)+V_(2)M_(2))/("Total Vol")`
`=((10xx0.1)+(40xx0.4))/50=0.34`
`pH=-log[3.7xx10^(-1)]=0.4685`