The ionic product of water at `80^(@)C` is `2.44xx10^(-13)`. What are the concentrations of hydronium ion and the hydroxide in pure water at `80^(@)C`?

Explanation

Ionic product of water at `80^(@)C=2.44xx10^(-13)`
`[H^(+)][OH^(-)]=2.44xx10^(-13)`
`[H^(+)][OH^(-)]=sqrt(2.44xx10^(-13))=4.99xx10^(-7)`