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Explain the following. PbCl4 is unstab...

Explain the following.
`PbCl_4` is unstable to heat.

Text Solution

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`Pb^(2+)` is more stable than `Pb^(4+)` due to inert pair effect. So `PbCl_2` is more stable than `PbCl_4`. Thus on heating `PbCl_4` converts into stable `PbCl_2` by losing `Cl_2`.
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