Give the Molecular Orbital Diagram of `N_2`. Calculate the bond order of `N_2`.

What is meant by the term Bond order? Calculate the bond orders in the following. (a) N_(2) " " (b) O_(2)" " (c) O_(2)^(+)" " and (c) O_(2)^(-)

A bonding molecular orbital is produced by

According to molecular orbital theory, atomic orbitals of nearly same energy of different atoms are combined and form molecule. In homodiatomic molecule two atomic orbitals which have wave function psi_(A) and psi_(B) are combined in two ways (psi_(A)pm psi_(B)) . They have two type of electron density, one is bonding [(psi_(A) pm psi_(B))^(2)] where e- density increase between nucleus. Another is antibonding [(psi_(A)pm psi_(B))^(2)] where e^(-) density decreases between nucleus. These molecular orbitals are filled according to Hund, Pauli, afbau principle. Existence of molecule depends on bond order. where bond order = ("Number of bonding "e^(-)"s- number of antibonding "e^(-)s)/(2) lf the molecule have unpaired electron it is paramagnetic otherwise diamagnetic Statement- 1: Removal of two e^(-) from N^(2) , magnetic behaviour does not change while addition of two electrons in O_(2) magnetic behaviour changes. Statement-2: In N_(2) removal of electron talces place from bonding orbital while addition of e^(-) in O_(2) is in antibonding orbital

The correct order of the energy of molecular orbitals in a molecules having four electrons